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Truncated cube

The truncated cube, or truncated hexahedron, is an Archimedean solid. It has 6 regular octagonal faces, 8 regular triangular faces, 24 vertices and 36 edges.

Contents


Area and volume

The area A and the volume V of a truncated cube of edge length a are:

A = 2(6+6\sqrt{2}+\sqrt{3})a^2 \approx 32.4346644a^2
V = \frac{1}{3}(21+14\sqrt{2})a^3 \approx 13.5996633a^3.

Cartesian coordinates

The following Cartesian coordinates define the vertices of a truncated hexahedron centered at the origin with edge length 2?:

(±?, ±1, ±1),
(±1, ±?, ±1),
(±1, ±1, ±?)

where ? = \sqrt2 - 1

Related polyhedra

Compare:


Cube

Truncated cube

cuboctahedron

Truncated octahedron

Octahedron

It shares the vertex arrangement with three uniform star polyhedrons:


(4.8/3.4/3.8/5)

(8/3.3.8/3.4)

(4.3/2.4.4)

See also

References

  • (Section 3-9)

External links

de:Hexaederstumpf eo:Senpintigita kubo es:Cubo truncado fr:Cube tronqué ko:?? ???? it:Cubo troncato nl:Afgeknotte hexaëder ja:????? pl:Sze?cian ?ci?ty pt:Cubo truncado th:?????????????????? zh:?????





Source: Wikipedia | The above article is available under the GNU FDL. | Edit this article



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